divisao polinómios 2ªparte

Area do circulo - Perimetro da circunferencia

 Pi       π = 3.14159  

Calculate area (A) and perimeter (P)

Calcular área (A) e perimetro (P)

Calculer la superficie (A) et le périmètre (P)

 R=3 m

P=2 * pi * R
P=2 * pi * 3
P=6 pi 
P=18,84954 metro

A= pi * R²
A= pi * 3 * 3
A= 9 pi
A= 28,27431 metro²

divisaopolinomios 1ª parte

video

Programa média ponderada de notas
Ler as 2 notas do aluno: N1, N2
Calcular a média ponderada do aluno

                                     media = ( N1 + 4*N2) / 5 

Weighted average program from 0 ~ 20 notes 
Read 2 student grades: N1, N2
Calculate the weighted average student

                                     final score = (N1 + N2 * 4) / 5

Programme moyen pondéré de 0 ~ 20 notes
Lire 2 notes des étudiants: N1, N2
Calculer l'étudiant moyen pondéré

                                      score final = (N1 + N2 * 4) / 5


             org 1000h
N1:    ds 1
N2:    ds 1
       
             org 3000h
start:    lda N1  
             mov b,a ; the N1 we save at the b register
         
             lda N2   
             add a  ; here accumulator=2*N2
             add a  ; here we have accumulator 4*N2
           
             add b  ; in the accumulator we have N1+4*N2

             add a  ; lets two multiply all by 2 and then we must divide by 10
      
                      ; accumulator have now 2(N1+4*N2).
                      ; lets go to divide the accumulator by 10
  
             mvi c,0      ;  we use the register c to count the times that we
                               ; subtract the accumulator by 10 
             mvi d,10    ; we use d register to made the subtraction as sub d 
                           
 loop:    cpi 10     ; to see if accumulator is less then 10, if carry then a<10 
             jc theend
             sub d    ; its equal to do sui 10, note d is 10 but less expensive time
             inr c
             jmp loop
       

theend: rst 1 ; the media is at: the integer part at c regist
                     ; and decimal part at the acumulator 
             end  ;

Com estes diodos consegue-se ter uma saída a nivel logico alto desde que uma das entradas esteja a nivel lógico alto. Para termos a saída a nível lógico baixo temos de ter as duas entradas a nível lógico baixo. Este circuito implementa a função lógica OU do ingês OR. A saída é "1" se A OU B a "1".

With these diodes can get an output logical high level as long as one of the inputs is the logic high level. To get the output to logic low level we must have both inputs to logic low. This circuit implements the logic OR function . The output is "1" if A OR B "1".

Avec ces diodes peuvent obtenir une sortie haut niveau logique aussi longtemps que l'une des entrées est le haut niveau de la logique. Pour obtenir la sortie à niveau logique bas, nous devons avoir les deux entrées à logique bas. Ce circuit met en oeuvre la fonction logique OU de l'anglais OR. La sortie est "1" si A ou B "1".


________________________________________________________________________________

 

Com estes diodos consegue-se ter uma saída a nivel logico alto só quando ambas as entradas estão a nivel lógico alto. Temos a saída a nível lógico baixo desde que uma das entradas esteja a nível lógico baixo. Este circuito implementa a função lógica E, do ingês AND. A saída é "1" se A E B a "1".

With these diodes is achieved by having a logical high level output only when both inputs are logic high level. We have the output to logic low since one of the inputs is a logic low. This circuit implements the logic function AND. The output is "1" if A AND B is "1".

Avec ces diodes est réalisé en ayant une sortie de haut niveau logique que lorsque les deux entrées sont la logique de haut niveau. Nous avons la sortie à l'état logique bas depuis l'une des entrées est un bas logique. Ce circuit met en oeuvre la fonction logique ET, le AND anglais. La sortie est à "1" si A et B à "1".

PT: Resolução de sistemas de 2 equações a 2 incógnitas pelo método dos determinantes. Regra de Cramer

EN: Resolution of 2 equations to 2 unknowns by the method of determining systems. Rule Cramer

FR:Résolution des équations 2 à 2 inconnues par la méthode de détermination systèmes. Règle Cramer


|-ax+k=by     
|cx-dy+w=0  

PT: Quando temos um sistema temos de o arrumar: x , y e termo independente

EN: When we have a system we have to fix: x, y independent term 

FR:Lorsque nous avons un système que nous avons à fixer: x, y terme indépendant

|-ax-by=-k       |-a   -b|
|cx-dy=-w       |c    -d|

  

     |-k   -b|

     |-w  -d|         (-k * -d ) - (-w * -b)

x= ------------  = ---------------------------------

      |-a   -b|        (-a * -d) - (c * -b)

      |c    -d|

     |-a   -k|
     |c    -w|         (-a * -w ) - (c * -k)
y= ------------  = ---------------------------------
      |-a   -b|        (-a * -d) - (c * -b)
      |c    -d|

PT: Resolução de sistemas de 2 equações a 2 incógnitas pelo método da adição
EN:Resolution of 2 equations with 2 unknowns by the addition method
FR:Résolution des équations 2 à 2 inconnues par la méthode des ajouts 


| x+y=12             há que passar este 2x para o outro lado
| y=2x <-- pass the 2x to the left side  
                            passer le 2x pour le autre cote


|   x+y=12             multiplicar aqui por -1
|-2x+y=0 <-- multiplication here by -1
                             faire la multiplication pour le -1

| x+y=12               somar as duas equações
|2x-y=0                  do the adition of this two equations      

----------------              faire la aditions de ce 2 equations
  3x  =12
 x=12/3 => x=4
                                
                                 multiplicar aqui por 2
|   x+y=12 <--  multiplication here by 2
|-2x+y=0                  multiplier ici pour 2


| 2x+2y=24           add the 2 equations  somar as 2 equações
|-2x+ y=0              ajouter les deux équations
-----------------
      3y=24  <=> y=24/3 => y=8